These MCQs are intended for checking your Chemistry subject, Chapter Solutions knowledge.

An X molal solution of a compound in benzene has mole fraction of solute equal to 0.2. The value of X is :

Which of the following form ideal solution?

Which of the following will form an ideal solution ?

Mole fraction of ethanol in ethanol water mixture is 0.25. Hence precentage concentration of ethanol by weight
of mixture is :

If vapour pressures of pure liquids ‘A’ & ‘B’ are 300 and 800 torr respectively at 25°C. When these two liquids are mixed at this temperature to form a solution in which mole percentage of ‘B’ is 92, then the total vapour pressure is observed to be 0.95 atm. Which of the following is true for this solution.

The vapour pressure of an ideal solution having 0.2 mole non-volatile solute & 0.8 mole solvent is 60 mm. The
vapour pressure of pure solvent at this temperature will be :

Azeotropic mixture are :

A mixture has 18 g water and 414 g ethanol. The mole fraction of water in mixture is (assume ideal behaviour of the mixture) :

Which of the following shows negative deviation from Raoult's law ?

8 g NaOH is dissolved in one litre of solution, its molarity is :

The vapour pressure of a pure liquid ‘A’ is 70 torr at 27°C. It forms an ideal solution with another liquid 'B'. The
mole fraction of 'B' is 0.2 and total vapour pressure of the solution is 84 torr at 27°C. The vapour pressure of pure
liquid 'B' at 27°C is :

What is the mole ratio of benzene (PB0= 150 torr) and toluene (PT0= 50 torr) in vapour phase if the given solution has a vapour pressure of 120 torr?

Which of the following solution containing components A and B follows Raoult’s law :

The vapour pressure of two pure liquids “A” and “B” are 100 and 80 torr respectively. The total pressure of the
solution obtained by mixing 2 mol of “A” and 3 mol of “B” would be :

For a solution of two liquids A and B. it was proved that P = XA(PA0– PB0) + PB0. The solution is :

Your score is


Try other Chapter